American Holiday: Difference between revisions
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{{Infobox | {{Infobox album | ||
| | | name = American Holiday | ||
| | | type = Unofficial bootleg | ||
| | | artist = [[Weezer]] | ||
| | | cover = R-7433122-1441419395-9479.png (1).jpg | ||
| | | alt = | ||
| | | released = [[1995]] | ||
| | | format = CD | ||
| | | recorded = [[August 12]], [[1994]] <small>(tracks 1–9)</small><br>[[December 5]], [[1994]] <small>(tracks 10–18)</small> | ||
| | | studio = | ||
| genre = | |||
| length = 1:03:03 | |||
| label = Tornado | |||
| producer = | |||
| reviews = | |||
| metascore = | |||
| song_reviews = | |||
| prev_title = | |||
| prev_year = | |||
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| next_year = | |||
}} | }} | ||
'''''American Holiday''''' is an unlicensed bootleg [[Weezer]] CD released by the record label Tornado in late [[1995]]. Band archivist and roadie [[Karl Koch]] recognizes it to be the second Weezer bootleg ever released, following ''[[Geezer]]'', which released earlier the same year.<ref name="TodayInWeezerHist">[[Weezer]]. (December 4, 2013). Social media post. Archived from the original on Weezerpedia at [[Historic event: 12/04/1994]].</ref> | '''''American Holiday''''' is an unlicensed bootleg [[Weezer]] CD released by the record label Tornado in late [[1995]]. Band archivist and roadie [[Karl Koch]] recognizes it to be the second Weezer bootleg ever released, following ''[[Geezer]]'', which released earlier the same year.<ref name="TodayInWeezerHist">[[Weezer]]. (December 4, 2013). Social media post. Archived from the original on Weezerpedia at [[Historic event: 12/04/1994]].</ref> | ||